2x-56=x^2+12x+32

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Solution for 2x-56=x^2+12x+32 equation: 



2x-56=x^2+12x+32

We move all terms to the left:

2x-56-(x^2+12x+32)=0

We get rid of parentheses

-x^2+2x-12x-32-56=0

We add all the numbers together, and all the variables

-1x^2-10x-88=0

a = -1; b = -10; c = -88;
Δ = b2-4ac
Δ = -102-4·(-1)·(-88)
Δ = -252
Delta is less than zero, so there is no solution for the equation

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